Calculus! Solve for x in function ln((x-6)^2)=16?
March 19th, 2010
i know that when you put e in both sides you can solve, but I need two values.
Thanks for any help :)
so e(ln((x-6)^2) = e^16
then square root of both sides
so (x-6) and sqrt ( e^16)
then add six to both sides
so x= sqrt ( e^16)+6
**** e cancels out ln ****
Ln(x-6)=8
x-6=e^8=2980.96
x=2986.96
e^ ln[ (x - 6)^2 ] = e^16
(x - 6)^2 = e^16
x - 6 = +/- sqrt[ e^16 ] = +/- e^8
x = 6 + e^8
x = 6 - e^8
These are our two solutions.
Hope this helps.
(x - 6)^2 = e^16 (I assume you are using base e.)
Then use the square root principal:
x - 6 = +/- e^8
or
x = 6 +/- e^8
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